(k^3-k^2-k-2)/(k-2)

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Solution for (k^3-k^2-k-2)/(k-2) equation: 


D( k )

k-2 = 0

k-2 = 0

k-2 = 0

k-2 = 0 // + 2

k = 2

k in (-oo:2) U (2:+oo)

(k^3-k^2-k-2)/(k-2) = 0

k^3-k^2-k-2 = 0

k^3-k^2-k-2 = 0

{ 1, -1, 2, -2 }

1

k = 1

k^3-k^2-k-2 = -3

1

-1

k = -1

k^3-k^2-k-2 = -3

-1

2

k = 2

k^3-k^2-k-2 = 0

2

k-2

k^2+k+1

k^3-k^2-k-2

k-2

2*k^2-k^3

k^2-k-2

2*k-k^2

k-2

2-k

0

k^2+k+1 = 0

DELTA = 1^2-(1*1*4)

DELTA = -3

DELTA < 0

k in { 2} 

k-2 = 0

1 = 0

k belongs to the empty set

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